sci.physics.particle

On Mar 6, 3:53 pm, va...@cox.net wrote:
> On Mar 6, 9:19 am, "Androcles" wrote:
>
>
>
> > "PD" wrote in message
>
> >news:d25d5e8d-69e8-4208-bf8e-0fd1a797767e@n58g2000hsf.googlegroups.com...
> > On Mar 6, 9:38 am, The Ghost In The Machine
>
> > wrote:
> > > In sci.physics.relativity, Eric Gisse
> > >
> > > wrote
> > > on Thu, 6 Mar 2008 06:50:41 -0800 (PST)
> > > <2b831503-d191-4816-9c13-99a0eed97...@s8g2000prg.googlegroups.com>:
>
> > > > On Mar 5, 9:55 pm, Koobee Wublee wrote:
> > > >> On Mar 4, 6:03 pm, carlip-nos...@physics.ucdavis.edu wrote:
>
> > > >> > I suggest that you try for a graceful retreat.
>
> > > >> Well, I found a mistake in the boundary condition. As you have
> > > >> suggested, I will execute a graceful retreat this time. In doing so,
> > > >> my instinct might still be correct about any high-speed particle
> > > >> having a discontinuity as its speed goes to the speed of light.
>
> > > > My god your arrogance is astounding. DO THE COMPUTATION.
>
> > > What math would you have him do? ;-) There is indeed a
> > > discontinuity in the SR energy equation
>
> > > E = m c^2 / sqrt(1-v^2/c^2)
>
> > > Going through infinity to become imaginary energy sounds like
> > > a pretty big discontinuity to me....
>
> > | There's no going *through* infinity. There is an *approach* to
> > | infinity. A function that has an infinite asymptote is not
> > | discontinuous.
>
> > y = tan(x) for x = 0 to pi has no discontinuity at pi/2?
> > Why yes, yes it does.
>
> Graph it nitwit.
>
> tan pi = .054886...
> tan pi/2 = .027422...
> tan pi/100 = .0005483...
> tan pi/1000 = .00005483...

Dude.

tan(x) = sin(x) / cos(x)

sin(pi/2) = 1
cos(pi/2) = 0

Plot it on a calculator.

>
>
>
> > Fucking idiot!
> > HAHAHAHAHAHA!- Hide quoted text -
>
> > - Show quoted text -