sci.physics.electromag

CV=Q so C=47E-3 V=3 so Q=0.141 colomb. Q=flux cut by rod, if the rod is
perpendicular to the field then the flux cut is length of rod times distance
moved. The flux/sq meter is the ciculation of the current/area so if there
are n turns with a current I the flux density=In/area of coil=nI/(pi .
(diameter/2)^2) so if d is the diameter and l is the length of the rod and
x distance moved then

Q = l.x.I.n/(pi . (d/2)^2) = 0.141

So if l=x=d/2 then d/2 . d/2 . In/(pi . d/2 . d/2)=0.141
so nI=pi . 0.141: nI=0.4429 for n=10 I=44.29 mA

Don't quote me, I'm ET.
--
Chris
http://www.myphilosophy.eu
wrote in message
news:53080be0-9ea4-4e35-bc56-521e9a3b769e@h11g2000prf.googlegroups.com...
>I have to mathematically model a metal rod moving inside a coil. When
> I move the rod through the field, the emf is induced between the ends
> of the rod causing current to flow. This will recharge a large
> capacitor able to supply the necessary current to a resistive load.
> Can somebody help me out to design the components of this system
> (using formulas if possible) in order to recharge a capacitor of 47mF
> with 3V? Any help is really appreciated.
> Nick